From the ground state electronic configuratio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The second ionization energy is the energy required to remove an electron from a unipositive ion $(M^+)$.$1$. For option $A$ $(Mg)$: $Mg^+ (1s^2,

Vedclass · Accepted Answer

$1s^2, 2s^2, 2p^6, 3s^1$

Vedclass · Answer

(B) The second ionization energy is the energy required to remove an electron from a unipositive ion $(M^+)$.$1$. For option $A$ $(Mg)$: $Mg^+ (1s^2, 2s^2, 2p^6, 3s^1) \rightarrow Mg^{2+} + e^-$. The electron is removed from the $3s$ orbital.$2$. For option $B$ $(Na)$: $Na^+ (1s^2, 2s^2, 2p^6) \rightarrow Na^{2+} + e^-$. The electron is removed from the stable noble gas configuration $(2p^6)$,which requires very high energy.$3$. For option $C$ $(Ne)$: $Ne^+ (1s^2, 2s^2, 2p^5) \rightarrow Ne^{2+} + e^-$. The electron is removed from the $2p$ orbital.$4$. For option $D$ $(F)$: $F^+ (1s^2, 2s^2, 2p^4) \rightarrow F^{2+} + e^-$. The electron is removed from the $2p$ orbital.Comparing these,removing an electron from the stable octet configuration of $Na^+$ requires the highest energy.

From the ground state electronic configuration of the elements given below,pick up the one with the highest value of second ionization energy.

Similar Questions

In comparison to boron,beryllium has

Which of the following elements are at the peaks of the ionization energy trend?

The correct decreasing order of the first ionisation enthalpies of the five elements $Be, B, C, N, F$ is:

The first ionisation energy of oxygen is less than that of nitrogen. Which of the following is the correct reason for this observation?

The first $I.E.$ of $Na, Mg, Al$ and $Si$ are in the order:

Vedclass Test Series

Exam Paper Generator

Online Exam Module